Tick (✓) the correct answer:6a2−13a+6=?(a) (2a + 3)(3a − 2)(b) (2a − 3)(3a + 2)(c) (3a − 2)(2a − 3)(d) (3a + 1)(2a − 3)
The correct option is (c) (3a − 2)(2a − 3)Given 6a2−13a+6=6a2−9a−4a+6=3a(2a−3)−2(2a−3)=(3a−2)(2a−3)
6a2−13a+6=?(a) (2a+3)(3a−2)(b) (2a−3)(3a+2)(c) (3a−2)(2a−3)(d) (3a+1)(2a−3)
Find the value of : (3a−12)(3a−12)