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Question

Factorization: (2a3)22(2a3)(a1)+(a1)2

A
(2a3)2
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B
(a2)2
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C
(a1)2
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D
(a3)2
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Solution

The correct option is B (a2)2
(2a3)22(2a3)(a1)+(a1)2

Let x=(2a3),y=(a1)

x22xy+y2

(xy)2

Substituting the values of x and y,we get

((2a3)(a1))2

(2a3a+1)2

(a2)2

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