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Question

two balls projected in vertical upward direction with same speed of 40 m/s, at interval of 2 sec. At what height and time will the projections collide

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Solution

Let the particle meet t0 seconds after the projection of the first particle,let they will meet at h height,h=ut0-12gt02 (1For second particleh=u(t0-t)-12g(t0-t)2 (2from (1 and (2ut0-12gt02 =u(t0-t)-12g(t0-t)2 t0=t2+ug=22+4010=5sec

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