Emma's friend Sara also participated in the long jump competition. In her last jump, she covered 6 feet and missed getting the second prize by 10 inches. (in inches) was required to bag the second prize.

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Solution

Distance Sara jump $= 6$ ft
Distance Sara missed $= 10$ in
Total distance required to bag the second prize
$= 6 f t + 10 i n$

Note: $1 ft = 12 in$
$6 ft = 12 \times 7 = 72$ in

So, total distance required to bag the second prize
$= 72 + 10$
$= 82$ inches

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Emma's friend Sara also participated in the long jump competition. In her last jump, she covered 6 feet and missed getting the second prize by 10 inches. (in inches) was required to bag the second prize.

Distance Sara jump =6 ft Distance Sara missed =10 in Total distance required to bag the second prize =6 ft+ 10 in Note: 1 ft=12 in 6 ft=12×7=72 in So, total distance required to bag the second prize =72+10 =82 inches

Distance Sara jump $= 6$ ft
Distance Sara missed $= 10$ in
Total distance required to bag the second prize
$= 6 f t + 10 i n$

Note: $1 ft = 12 in$
$6 ft = 12 \times 7 = 72$ in

So, total distance required to bag the second prize
$= 72 + 10$
$= 82$ inches