Energy of photon whose frequency is 1012 MHz- will beA- 4-14 - 102 eVB- 4-14 - 103 MeVC- 4-14 - 103 KeVD- 4-14 - 103 eV

The correct option is D 4.14×10^3 eV E(eV)=hv/e=6.0×10^ 34×10^12×10^6/1.6×10^ 19=4.14×10^3 eV. ...

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Standard XII

Physics

The Photon Model

Energy of pho...

Question

Energy of photon whose frequency is $10^{12} M H z$ , will be

$4.14 \times 10^{3} K e V$

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$4.14 \times 10^{2} e V$

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$4.14 \times 10^{3} M e V$

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$4.14 \times 10^{3} e V$

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Solution

The correct option is D
$4.14 \times 10^{3} e V$

$E (e V) = \frac{h v}{e} = \frac{6.0 \times 10^{- 34} \times 10^{12} \times 10^{6}}{1.6 \times 10^{- 19}} = 4.14 \times 10^{3} e V .$

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[Take

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Energy of photon whose frequency is 1012MHz, will be

The correct option is D 4.14×103eV E(eV)=hve=6.0×10−34×1012×1061.6×10−19=4.14×103eV.

Energy of photon whose frequency is $10^{12} M H z$ , will be

The correct option is D
$4.14 \times 10^{3} e V$

$E (e V) = \frac{h v}{e} = \frac{6.0 \times 10^{- 34} \times 10^{12} \times 10^{6}}{1.6 \times 10^{- 19}} = 4.14 \times 10^{3} e V .$