Question

Energy of photon whose frequency is ${10}^{12}MHz$, will be

• A. $4.14\times {10}^{3}KeV$
• B. $4.14\times {10}^{2}eV$
• C. $4.14\times {10}^{3}MeV$
• D. $4.14\times {10}^{3}eV$

Answer 1

The correct option is D

$4.14\times {10}^{3}eV$

$E\left(eV\right)=\frac{hv}{e}=\frac{6.0\times {10}^{-34}\times {10}^{12}\times {10}^6}{1.6\times {10}^{-19}}=4.14\times {10}^{3}eV.$