Question

Energy released in the fission of a single ${}_{92}{U}^{235}$ nucleus is $200MeV$. The fission rate of ${}_{92}{U}^{235}$ fuelled reactor operating at a power level of $5watt$ is

• A. $1.56\times {10}^{14}/sec$
• B. $1.56\times {10}^{11}/sec$
• C. $1.56\times {10}^{20}/sec$
• D. $1.56\times {10}^{-17}/sec$

Answer 1

Answer: (A)

$1.56\times {10}^{14}/sec$

Power $=$ energy released per second so,

$5$ joule of energy is releasing per second and one nucleus produces $200Mev$ of energy.

The fission rate $=\frac{5joule}{200Mev}$

$\Rightarrow \eta =\frac{5}{20\times {10}^6\times 1.6\times {10}^{-19}}\Rightarrow \eta =\frac{5}{12}\times {10}^{15}\Rightarrow \eta =1.56\times {10}^{14}/sec$