Assuming that about 200MeV of energy is released per fission of 92U235 nuclei, the mass of U235 consumed per day in a fission reactor of power 1MW will be approximately
A
10−2g
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B
1g
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C
100g
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D
10,000g
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Solution
The correct option is B1g Energy released per disintegration =200MeV=200×(1.6×10−13)J=3.2×10−11J Total Energy required =1MW=106J/s No. of integrations required =N=1063.2×10−11=3.125×1016 Moles (n) =NNA=5.188×10−8moles/s Mass consumption =nM=1.22×10−5gms/s Total consumption in a day =1.22×10−5gm/s×(24×3600)=1.053gms