Energy required to remove one from neutral helium atom is $E_{1} e V$ energy required to remove both electrons from a neutral form a neutral helium atom is

2 E_{1}

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3 E_{2}

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(E_{1} + 54.4) e V

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(E_{1} + 13.6) e V

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Solution

The correct option is B $(E_{1} + 13.6) e V$
So $,$ $E_{t o t a l} = (E_{1} + 13.6) e v$
Hence,
option $(D)$ is correct answer.

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Energy required to remove one from neutral helium atom is E1eV energy required to remove both electrons from a neutral form a neutral helium atom is

The correct option is B (E1+13.6)eVSo, Etotal=(E1+13.6)evHence,option (D) is correct answer.

Energy required to remove one from neutral helium atom is $E_{1} e V$ energy required to remove both electrons from a neutral form a neutral helium atom is

The correct option is B $(E_{1} + 13.6) e V$
So $,$ $E_{t o t a l} = (E_{1} + 13.6) e v$
Hence,
option $(D)$ is correct answer.