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Question

Enthalpy change for the reaction H+(aq)+OH(aq)H2O(l) IS57.3 kJ mol1. If 1 L of 0.5 MJNO3 is mixed with 2L of 0.1 MKOH, the enthalpy change would be


A

-28.35 kJ

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B

28.65 kJ

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C

-11.46 kJ

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D

11.46 kJ

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Solution

The correct option is C

-11.46 kJ


Number of equiv. of HNO3=1×0.5=0.5; equivalents of KOH=2×0.1=0.2 (limiting reagent)

Enthalpy change = Number of equivalents ×ΔHN

=0.2×(57.3)=11.46 kJ


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