Question

If enthalpy of neutralization of ${CH}_{3}COOH$ by $NaOH$ is $-49.86kJ/mol$ then enthalpy of ionization of ${CH}_{3}COOH$ is:

[Note : For strong acid and strong base neutralization net chemical change is :

$H^{+}\left(aq\right)+{OH}^{-}\left(aq\right)⟶H_{2}O\left(l\right);{\Delta }_r{H}^o=-55.84kJ/mol$].

• A. $+5.98kJ/mol$
• B. $-5.98kJ/mol$
• C. $+105kJ/mol$
• D. none of the above

Answer 1

The correct option is A $+5.98kJ/mol$