Question

If enthalpy of neutralization of $C{H}_{3}COOH$ by $HCl$ is $-49.86$ kJ/mol, then enthalpy of ionization of $C{H}_{3}COOH$ is:

• A. $5.98$ kJ/mol
• B. $-5.98$ kJ/mol
• C. $105.7$ kJ/mol
• D. none of these

Answer 1

Answer: (A)

$5.98$ kJ/mol

$\Delta {H^o}_{neutralization}=$ $-49.86=\Delta H_{ion}-55.84$
$\Delta H_{ion}=55.84-49.86=5.98$ KJ/mol