Question

Enthalpy change in kJ is_________.

(Give answer as greatest integer)

Answer 1

At 298 K, $E=0.0455V$
At 308 K, $E=0.0455+3.38\times {10}^{-4}\times 10=0.04888V$
$\Delta G=-nFE$
At 298 K, $\Delta G=2\times 96500\times 0.0455=-8781.5J/mol$
At 308 K, $\Delta G=2\times 96500\times 0.04888=-9433.84J/mol$
$\Delta H=\Delta H-T\Delta S$
$-8781.5=\Delta H-298\Delta S$.......(1)
$-9433.84=\Delta H-308\Delta S$......(2)
Subtract equation (2) from equation (1)
$652.34=10\Delta S$
$\Delta S=65.234$
$\Delta H=-8781.5+298\left(65.234\right)=10.65kJ/mol$

So the correct answer is $11$.