Enthalpy of sublimation of a substance is equal to :

Enthalpy of fusion + enthalpy of vapourisation

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Enthalpy of fusion

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Enthalpy of vapourisation

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Twice the enthalpy of vapourisation

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Enthalpy of fusion + enthalpy of vapourisation
$S o l i d S u b l i m a t i o n - ------ \to V a p o u r$
This process occurs in two steps,
Step 1 : $S o l i d F u s i o n - --- \to L i q u i d$
Step 2 : $L i q u i d V a p o r i s a t i o n - ------- \to V a p o u r$
Thus, Enthalpy of sublimation = Enthalpy of fusion + Enthalpy of vaporisation.

Suggest Corrections

Similar questions

Enthalpy of sublimation of a substance is equal to
(a) enthalpy of fusion + enthalpy of vaporisation
(b) enthalpy of fusion
(c) enthalpy of vaporisation
(d) twice the enthalpy of vaporisation

Q. Define enthalpy of sublimation. How is it related to enthalpy of fusion and enthalpy of vaporization?

Q. At

298 K

, the enthalpy of fusion of a solid

(X)

2.8 {KJ mol}^{- 1}

and the enthalpy of vaporisation of the liquid

(X)

98.2 K J {mol}^{- 1}

. The enthalpy of sublimation of the substance

(X)

K J {mol}^{- 1}

is . (in nearest integer)

Q. For which of the following substances, the enthalpy of atomization also represents the enthalpy of sublimation?

Q. The sublimation energy of

I_{2} (s)

57.3 k J / m o l

and the enthalpy of fusion is

15.5 k J / m o l

. The enthalpy of vaporisation of

I_{2}

is:

Join BYJU'S Learning Program