Question

Equal amounts of zinc is allowed to react with excess of $H_{2}S{O}_4$ and excess of $NaOH$ separately. The ratio between the weights of $H_2$ formed is:

• A. 1 : 2
• B. 1 : 1
• C. 1 : 3
• D. 2 : 1

Answer 1

The correct option is B 1 : 1

The reaction between zinc and sulfuric acid is $Zn+H_{2}S{O}_4\to ZnS{O}_4+H_2$.
Thus, one mole of zinc reacts with excess of sulfuric acid to produce one mole of hydrogen.

The reation between zinc and NaOH is $Zn+2NaOH\to N{a}_{2}Zn{O}_2+H_2$.
Thus, one mole of zinc reacts with excess of sodium hydroxide to produce one mole of hydrogen.

Hence, the ratio between the weights of hydrogen formed is $1:1$.