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Question

Equal masses of gaseous N2,NH3 and N2O are injected into an evacuated container to produce a total pressure of 3 atm. What is the correct order of partial pressure of these gases?

A
PN2=PNH3=PN2O
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B
PN2<PNH3<PN2O
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C
PNH3<PN2<PN2O
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D
PN2O<PN2<PNH3
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Solution

The correct option is D PN2O<PN2<PNH3
Partial pressure = mole fraction × total pressure

PN=nNntotal×3=[WNMN]ntotal×3

The gas which have higher molar mass, will exert lower partial pressure.


PNH3>PN2>PN2O

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