Equal masses of water and a liquid of relative density $2$ are mixed together, then what is the density of the mixture (in $g {c m}^{- 3}$ )?

2 / 3

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4 / 3

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3 / 2

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3

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Solution

The correct option is B $4 / 3$
$\frac{ρ_{1}}{ρ_{2}} = 2. & m_{1} = m_{2} = m (l e t) & ϱ_{2} = 1 g / c c$
So $\frac{ρ_{1}}{ρ_{2}} = \frac{m_{1} / v_{1}}{m_{2} / v_{2}} = \frac{v_{2}}{v_{1}} = 2 \Rightarrow v_{1} = \frac{v_{2}}{2}$
So density of mixture = $\frac{m + m}{v_{1} + v_{2}} = \frac{2 m}{\frac{3 v_{2}}{2}}$
= $\frac{4}{3} ρ_{2} = \frac{4}{3}$

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Equal masses of water and a liquid of relative density 2 are mixed together, then what is the density of the mixture (in gcm−3)?

The correct option is B 4/3ρ1ρ2=2.&m1=m2=m(let)&ϱ2=1g/ccSo ρ1ρ2=m1/v1m2/v2=v2v1=2⇒v1=v22So density of mixture = m+mv1+v2=2m3v22 = 43ρ2=43

Equal masses of water and a liquid of relative density $2$ are mixed together, then what is the density of the mixture (in $g {c m}^{- 3}$ )?