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Question

Equal volumes of 0.50 M HCl, 0.25 M NaOH and 0.75 M NaCl are mixed. The molarity of the resultant NaCl solution is

A
0.75 M
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B
0.33 M
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C
0.50 M
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D
2.00 M
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Solution

The correct option is B 0.33 M
Let’s take the volume as V L of each solution.
Moles of HCl, NaOH and NaCl present initially = 0.50V, 0.25V and 0.75V respectively.
HCl+NaOHNaCl
0.50V 0.25V - (number of moles before reaction)
HCl and NaOH react to produce 0.25V M of NaCl
Total moles of NaCl in the solution = 0.25V (after reaction) + 0.75V (given)
Total moles of NaCl in the solution = V moles
Molarity=total moles of NaCltotal volume in L=V3VMM=13M=0.33 M

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