Question

Equation $12x^2-10xy+2y^2+11x-5y+2=0$ represent a pair of straight lines. Find the pair of angle bisector.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Given equation is $12x^2-10xy+2y^2+11x-5y+2=0$

Quadratic equation in x

$12x^2+(11-10y)x+2y^2-5y+2=0$

$x=\frac{-(11-10y)\pm \sqrt{(11-10y{)}^2-4\times 12(2y^2-5y+2)}}{2\times 12}$

$x=\frac{-(11-10y)\pm \sqrt{121+100y^2-220y-96y^2+240y-96}}{2\times 12}$

= $\frac{10y-11\pm \sqrt{4y^2+20y+25}}{24}$

= $\frac{10y-11\pm \sqrt{(2y+5{)}^2}}{24}$