Question

Equation of a line which is parallel to the line $\frac{x-2}{3}=\frac{y+1}{1}=\frac{z-7}{9}$, which passes through the point $\left(3,0,5\right)$ is

• A. $\frac{x-2}{3}=\frac{y+1}{0}=\frac{z-7}{5}$
• B. $\frac{x-2}{0}=\frac{y+1}{1}=\frac{z-7}{4}$
• C. $\frac{x-3}{3}=\frac{y-0}{1}=\frac{z-5}{9}$
• D. $\frac{x-3}{0}=\frac{y-0}{1}=\frac{z-5}{9}$

Answer 1

Answer: (C)

$\frac{x-3}{3}=\frac{y-0}{1}=\frac{z-5}{9}$

Equation of the line : $\frac{x-2}{3}=\frac{y+1}{1}=\frac{z-7}{9}$

DR $=(3,1,9)$

$\therefore$ Equation of the line parallel to $\frac{x-2}{3}=\frac{y+1}{1}=\frac{z-7}{9}$ and passing through $(3,0,5)$ is

$\frac{x-3}{3}=\frac{y-0}{1}=\frac{z-9}{9}$

Since DR will be same because they are parallel to each other