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Uniform and Non Uniform

Equation of p...

Question

Equation of position (x) with time (t) is given by equation $x = 3 t^{2} + 7 t^{2} + 5 t + 8 m$ . The acceleration at time t= $1$ sec is :

20 m / s e c^{2}

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32 m / s e c^{2}

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Zero

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14 m / s e c^{2}

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Solution

The correct option is A $20 m / s e c^{2}$
The relation between the time and position is given by the equation,
$x = 3 t^{2} + 7 t^{2} + 5 t + 8$
Velocity, $v = \frac{d x}{d t}$
$v = 6 t + 14 t + 5$
Acceleration, $a = \frac{d v}{d t}$
$a = 6 + 14$
$a = 20 m / s^{2}$

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Equation of position (x) with time (t) is given by equation x=3t2+7t2+5t+8m. The acceleration at time t=1 sec is :

The correct option is A 20m/sec2The relation between the time and position is given by the equation,x=3t2+7t2+5t+8Velocity, v=dxdtv=6t+14t+5Acceleration, a=dvdta=6+14a=20m/s2

Equation of position (x) with time (t) is given by equation $x = 3 t^{2} + 7 t^{2} + 5 t + 8 m$ . The acceleration at time t= $1$ sec is :

The correct option is A $20 m / s e c^{2}$
The relation between the time and position is given by the equation,
$x = 3 t^{2} + 7 t^{2} + 5 t + 8$
Velocity, $v = \frac{d x}{d t}$
$v = 6 t + 14 t + 5$
Acceleration, $a = \frac{d v}{d t}$
$a = 6 + 14$
$a = 20 m / s^{2}$