Question

Equation of the chord of the circle $x^2+y^2+4x-6y-9=0$ bisected at $(0,1)$ is

• A. $y-1=x$
• B. $y+1=x$
• C. $y+1=2x$
• D. $y-1=3x$

Answer 1

The correct option is A $y-1=x$

Equation of chord with given mid point is,

$T=S_1$
$\Rightarrow x\left(0\right)+y\left(1\right)+2(x+0)-3(y+1)-9=0+1+0-6-9$
$\Rightarrow y+2x-3y-3-9=1-15$
$\Rightarrow 2x-2y-12=1-15$
$\Rightarrow 2x-2y+2=0$
$\Rightarrow x-y+1=0$