Question

Equation of the line passing through (–1, 1) and perpendicular to the line 2x + 3y + 4 = 0, is

• A. 2(y – 1) = x + 1
• B. 3(y –1)= –2(x + 1)
• C. y – 1 = 2(x + 1)
• D. 3(y – 1) = x + 1

Answer 1

The correct option is A 2(y – 1) = x + 1

The slope of line 2x + 3y + 4 = 0 is
$m=$ $-\frac{2}{3}$
Now the equation of line passing through (-1,1) is y-1=m(x+1), but
$m=-\frac{1}{\frac{-2}{3}}=\frac{3}{2}$.
Therefore the required equation is 2(y – 1) = 3(x + 1).