Equation of the line passing through (–1, 1) and perpendicular to the line 2x + 3y + 4 = 0, is
A
2(y – 1) = 3(x + 1)
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B
3(y –1)= –2(x + 1)
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C
y – 1 = 2(x + 1)
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D
3(y – 1) = x + 1
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Solution
The correct option is A 2(y – 1) = 3(x + 1) The gradient of line 2x + 3y + 4 = 0 is −23. Now the equation of line passing through (-1,1) is y-1=m(x+1), but m=−1−23=32. Therefore the required equation is 2(y – 1) = 3(x + 1).