Equation of the line passing through (–1, 1) and perpendicular to the line 2x + 3y + 4 = 0, is

2(y – 1) = x + 1

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3(y –1)= –2(x + 1)

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y – 1 = 2(x + 1)

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3(y – 1) = x + 1

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Solution

The correct option is A 2(y – 1) = x + 1
$T h e g r a d i e n t o f l i n e 2 x + 3 y + 4 = 0 i s - \frac{2}{3} .$ $N o w t h e e q u a t i o n o f l i n e p a s s i n g t h r o u g h (- 1, 1) i s y - 1 = m (x + 1), b u t m = - \frac{1}{\frac{- 2}{3}} = \frac{3}{2} .$ $T h e r e f o r e t h e r e q u i r e d e q u a t i o n i s 2 (y - 1) = 3 (x + 1) .$

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Similar questions

2 x + 3 y + 5 = 0

(1, 1)

Equation of the line passing through (1,1,1) and perpendicular to $2 x - 3 y + z = 0$ is

y = 3 x + 5

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