CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equation of the line which passes through the point with p.v. (2, 1, 0) and perpendicular to the plane containing the vectors ˆi+ˆjandˆj+ˆk is

A
r=(2,1,0)+t(1,1,1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
r=(2,1,0)+t(1,1,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
r=(2,1,0)+t(1,1,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
r=(2,1,0)+t(1,1,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A r=(2,1,0)+t(1,1,1)
if line perpendicular to plane then eq
r=position vector a+t(normal vector n)
normal vector of plane
Given a=^i+^j
b=^j+^k
n=a×b
a×b=∣ ∣ ∣^i^j^k110011∣ ∣ ∣
a×b=^i(10)^j(10)+^k(10)
a×b=^i^j+^k
eq become
r=(2,1,0)+t(1,1,1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon