Question

Equilateral triangle ABD and ACE are drawn on side AB and AC respectively of a $\Delta ABC$ outside it. then, $\angle DAC=\angle EAB$

If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Given: ABD and ACE are equilateral triangles.
$\angle DAC=\angle DAB+\angle BAC$
$\angle DAC=60+\angle BAC$ ($△ABD$ is an equilateral triangle)
Now, $\angle EAB=\angle EAC+\angle CAB$
$\angle EAB=60+\angle BAC$ ($△ACE$ is an equilateral triangle)
Thus, $\angle DAC=\angle EAB$