Question

Equilibrium constant for the reaction is correctly given by the expression:
$H_2+I_2\rightleftharpoons 2HI$

• A. $K_c=\frac{\left[H_2\right]\left[I_2\right]}{\left[HI\right]}$
• B. $K_c=\frac{\left[H_2\right]\left[I_2\right]}{\left[2HI\right]}$
• C. $K_c=\frac{\left[H_2\right]\left[I_2\right]}{[HI{]}^2}$
• D. $K_c=\frac{[HI{]}^2}{\left[H_2\right]\left[I_2\right]}$

Answer 1

The correct option is D $K_c=\frac{[HI{]}^2}{\left[H_2\right]\left[I_2\right]}$

By law of chemical equilibrium,
$K_c=\frac{[HI{]}^2}{\left[H_2\right]\left[I_2\right]}$