Question

Equilibrium constant for the reaction
$OC{I}_{aq}^{-}+H_2{O}_l\rightleftharpoons HOC{I}_{\left(aq\right)}+O{H}_{aq}^{-}is$
$8.0\times {10}^{-5};Hence{K}_{a}forHOCIis$ -

• A. $1.2\times {10}^{-10}$
• B. $8\times {10}^9$
• C. $\frac{1}{8\times {10}^{-5}}$
• D. $8\times {10}^{-5}$

Answer 1

The correct option is A $1.2\times {10}^{-10}$

$K_a=\frac{K_w}{K_c}$
$=\frac{{10}^{-14}}{8\times {10}^{-5}}=1.2\times {10}^{-10}$