wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equilibrium constant, KC for the reaction
N2(g)+3H2(g)2NH3(g) at 500 K is 0.061 L2 mol2.
At a particular time, the analysis shows that composition of the reaction mixure is 3.0 mol L1 N2,2.0 mol L1H2 and 0.5 mol L1 NH3. What will be the direction of equilibrium?

A
at equilibrium
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
not at equilibrium, backward shift
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
not at equilibrium, forward shift
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
can not be predicted
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C not at equilibrium, forward shift
N2(g)+3H2(g)2NH3(g)t=teq 3M 2M 0.5MQ=0.5×0.53×23=13×8×4=196
Q < K, system is not at equilibrium and equilibrium will be reached by shifting in forward direction

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Le Chateliers Principle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon