Question

Equilibrium constant of a reversible reaction:

• A. Increases with increase of temperature
• B. Decreases with decreases of temperature
• C. May increases or decrease with temperature
• D. Is independent of temperature

Answer 1

The correct option is C May increases or decrease with temperature

$K=V/\left[A\right]$, with increase in temperature at a given concentration, velocity increases and Hence rate constant increases i.e. rate constant depends upon temperature. For a reversible reaction $K_{equi}=K_f/K_b$ and with increase in temperature $K_f$ and $K_b$ may increase or decrease.