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Standard XII

Chemistry

Law of Mass Action

Equilibrium c...

Question

Equilibrium constants for four different reactions are given as:
$K_{1} = 10^{6}, K_{2} = 10^{- 4}, K_{3} = 10, K_{4} = 1$ . Which reaction will take maximum time to attain equilibrium?

K_{1} = 10^{6}

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K_{2} = 10^{- 4}

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K_{3} = 10

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Can't predict

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Solution

The correct option is B Can't predict
Equilibrium constant only predict the extent of progress of reaction at equilibrium conditions. It does not predicts the time taken by reaction to attain equilibrium.

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Similar questions

The equilibrium constants for the reactions are:

$H_{3} P O_{4}_{1} H^{+} + H_{2} P O_{4}^{-}; K_{1} H_{2} P O_{4}^{-}_{2} H^{+} + H P O_{4}^{2 -}; K_{2} H P O_{4}^{2 -}_{3} H^{+} + P O_{4}^{3 -}; K_{3}$

The equilibrium constant for, $H_{3} P O_{4} ⇌ 3 H^{+} + P O_{4}^{3 -}$ will be:

Q. For the hypothetical reactions, the equilibrium constant (K) values are given:

A ⇌ B; K_{1} = 2; B ⇌ C; K_{2} = 4; C ⇌ D; K_{3} = 3

The equilibrium constant (K) for the reaction

A ⇌ D

is:

Q. Equilibrium constants for the following reaction at 1200 K are given.

2 H_{2} O (g) ⇋ 2 H_{2} (g) + O_{2} (g); K_{1} = 6.4 \times 10^{- 8}

2 C O_{2} (g) ⇋ 2 C O (g) + O_{2} (g); K_{2} = 1.6 \times 10^{- 6}

The equilibrium constant for the reaction

H_{2} (g) + C O_{2} (g) ⇋ C O (g) + H_{2} O (g)

at 1200 K will be:

Q. For the hypothetical reactions, the equilibrium constant (K) values are given:

A ⇌ B; K_{1} = 2; B ⇌ C; K_{2} = 4; C ⇌ D; K_{3} = 3

The equilibrium constant (K) for the reaction

A ⇌ D

is:

Q. For a reactions, the equilibrium constant

(K)

values are given:

A ⇌ B; K_{1} = 2 B ⇌ C; K_{2} = 4 C ⇌ D; K_{3} = 3

Then calculate the equilibrium constant for the reaction

A ⇌ D

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Equilibrium constants for four different reactions are given as:K1=106,K2=10−4,K3=10,K4=1. Which reaction will take maximum time to attain equilibrium?

The correct option is B Can't predictEquilibrium constant only predict the extent of progress of reaction at equilibrium conditions. It does not predicts the time taken by reaction to attain equilibrium.

Equilibrium constants for four different reactions are given as:
$K_{1} = 10^{6}, K_{2} = 10^{- 4}, K_{3} = 10, K_{4} = 1$ . Which reaction will take maximum time to attain equilibrium?

The correct option is B Can't predict
Equilibrium constant only predict the extent of progress of reaction at equilibrium conditions. It does not predicts the time taken by reaction to attain equilibrium.