Question

Equivalent mass of $K_{2}C{r}_2{O}_7$ in acideic solution in:

• A. molecular mass/2
• B. molecular mass/4
• C. molecular mass/1
• D. molecular mass/6

Answer 1

The correct option is D molecular mass/6

In acidic solution the reaction of $K_{2}C{r}_2{O}_7$ is given as,

$K_{2}C{r}_2{O}_7+4H_{2}S{O}_4\to K_{2}S{O}_4+C{r}_2(S{O}_4{)}_3+4H_{2}O+3(O)$

Here, $K_{2}C{r}_2{O}_7$ accepts 6$e^{-}$

Therefore, Equivalent mass$=\frac{\text{molecular mass}}{6}$