Equivalent mass of $K M n O_{4}$ in alkaline medium is $52.66$ or $\frac{M}{3}$ .

True

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False

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Solution

The correct option is B False
In a strongly basic solution, permanganate (VII) is reduced to the green Mn(VI) ion, $M n O_{4}^{2}$ .
$M n O_{4}^{-} + e^{-} \to M n O_{4}^{2 -}$
As we know,
$E q . w t . = \frac{m o l a r w t .}{n - f a c t o r} = \frac{M}{1} = M$

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