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Classification of Hydrocarbons

Equivalent ma...

Question

Equivalent mass of Na2CO3 when titrated with HCl using phenolphthalein indicator will be

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Solution

Na2CO3 + HCl ---------------------> NaHCO3 + NaCl
this will be the reaction
so equivalent mass will be same as 106

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Similar questions

Q. Calculate the equivalent mass of

N a_{2} C O_{3}

when it is titrated against

H C l

in presence of phenolphthalein.

25 m L

of a mixture of

N a O H

N a_{2} C O_{3}

when titrated with

N / 10 H C l

using phenolphthalein indicator required

25 m L H C l

. The same volume of mixture when titrated with

N / 10 H C l

using methyl orange indicator required

30 m L

H C l

. Calculate the amount of

N a_{2} C O_{3}

N a O H

in one litre of this mixture.

Q. Assertion :In the titration of

N a_{2} C O_{3}

H C l

using methyl orange indicator, the volume required at the equivalence point is twice that of the acid required using phenolphthalein indicator. Reason: Two moles of

H C l

is required for the complete neutralization of

1

N a_{2} C O_{3}

.

Q. Assertion :In the titration of

N a_{2} C O_{3}

H C l

using methyl orange indicator, the volume required at the equivalence point is twice that of the acid required using phenolphthalein indicator. Reason:

2

H C l

am required for complete neutralization of one mol of

N a_{2} C O_{3}

.

10 g

N a_{2} C O_{3}

N a O H

was titrated against

H C l

by using phenolphthalein followed by adding methyl orange after first equivalence point,

7.7818 g

H C l

was consumed in total. Find the mass of

N a_{2} C O_{3}

in the mixture.

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