Equivalent mass of $O_{3}$ in the reaction, $2 O_{3} ⟶ 3 O_{2}$ , is:

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Solution

$2 O_{3} ⟶ 3 O_{2}$
As two moles of ozone forms three moles of oxygen so, equivalent weight of ozone $= 2 \times 48 \times \frac{8}{3} \times 32 = 8$ g.

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Similar questions

2 O_{3} \to 3 O_{2}

O_{3} ⇌ O_{2} + [O] (f a s t)

[O] + O_{3} \to 2 O_{2} (s l o w)

{2 O}_{3} ⟶ {3 O}_{2}

O_{3} ⇌ O_{2} + O

O + O_{3} ⇌ {2 O}_{2}

2 O_{3} \to 3 O_{2}

O_{3} ⇌ O_{2} + O

O + O_{3} \to 2 O_{2}

2 O_{3} \to 3 O_{2}

O_{3} ⇌ O_{2} + O

O + O_{3} \to 2 O_{2}

The reaction ; $2 O_{3}$ → $3 O_{2}$ , is assigned the following mechanism.

(I) $O_{3} ⇋ O_{2} + O (i i) O_{3} + O s l o w ⇌ 2 O_{2}$

The rate law of the reaction will therefore be

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