Question

Equivalent weight of hydrated oxalic acid is:

• A. $44$
• B. $45$
• C. $63$
• D. $126$

Answer 1

Answer: (C)

$63$

Equivalent weight $=\frac{Molecularweight}{numberofequivalentmoles}$

The oxalic acid $HOOC-COOH.2H_{2}O$ has two moles of acidic $H^{+}$ that means one mole of oxalic acid can neutralize $2mols$ of $O{H}^{-}$. The number of equivalent moles$=2$

Equivalent weight of oxalic acid $=\frac{126}{2}=63g/eqmol$