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Decarboxylation

Equivalent we...

Question

Equivalent weight of pyrophosphoric acid, $(H_{4} P_{2} O_{7})$ is :

\frac{m o l e c u l a r w e i g h t}{1}

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\frac{m o l e c u l a r w e i g h t}{2}

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\frac{m o l e c u l a r w e i g h t}{4}

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\frac{m o l e c u l a r w e i g h t}{3}

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Solution

The correct option is C $\frac{m o l e c u l a r w e i g h t}{4}$
Basicity of $H_{4} P_{2} O_{7}$ is 4.

Therefore, equivalent weight of pyrophosphoric acid is $\frac{Molecular weight}{4}$ .

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Similar questions

H_{3} P O_{2} = \frac{m o l e c u l a r w e i g h t}{1}

H_{3} P O_{3} = \frac{m o l e c u l a r w e i g h t}{2}

H_{3} P O_{4} = \frac{m o l e c u l a r w e i g h t}{3}

= \frac{M o l e c u l a r w e i g h t}{A c i d i t y}

2 {N H}_{3} ⟶ N_{2} + 2 {N H}_{3}

{N H}_{3}

= \frac{M o l e c u l a r w e i g h t}{y}

y

N H_{3}

N_{2} \to N H_{3}

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= \frac{Molecular weight}{Number of electrons lost or gained per molecule}

N a_{2} S_{2} O_{3}

K_{2} C r_{2} O_{7}

K_{2} C r_{2} O_{7}

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