Ethane burns in oxygen to form CO2 and H2O according to the equation- 2C2H6-7O2- 4CO2-6H2O-If 1250cc of oxygen is burnt with 300cc of ethane-Calculate-i the volume of CO2 formed-ii the volume of unused O2-

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Ethane burns ...

Question

Ethane burns in oxygen to form $C O_{2}$ and $H_{2} O$ according to the equation:
$2 C_{2} H_{6} + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$ .
If $1250$ cc of oxygen is burnt with $300$ cc of ethane.
Calculate:
(i) the volume of $C O_{2}$ formed.
(ii) the volume of unused $O_{2}$ .

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Solution

Molecular weight of ethane is 30 g/mol and of $C O_{2}$ is 44 g/mol, $O_{2}$ is 32 g/mol
(i) In the reaction, the number of moles of $C O_{2}$ formed is twice as that of ethane, therefore volume will be twice as well
300 cc of ethane will burn to give 600 cc $C O_{2}$
(ii) In the reaction, the number of moles of $O_{2}$ used are 3.5 times as that of ethane, therefore volume will be 3.5 times as well.
To burn 300 cc of ethane amount of oxygen required is $300 \times 3.5 = 1050 c c$ . Unused oxygen is:
$1250 - 1050 = 200 c c$

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Ethane burns in oxygen to form CO2 and H2O according to the equation:2C2H6+7O2→4CO2+6H2O.If 1250cc of oxygen is burnt with 300cc of ethane.Calculate:(i) the volume of CO2 formed.(ii) the volume of unused O2.

Ethane burns in oxygen to form $C O_{2}$ and $H_{2} O$ according to the equation:
$2 C_{2} H_{6} + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$ .
If $1250$ cc of oxygen is burnt with $300$ cc of ethane.
Calculate:
(i) the volume of $C O_{2}$ formed.
(ii) the volume of unused $O_{2}$ .