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Question

Ethanol on reaction of acidified potassium dichromate form:

A
ethane
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B
ethene
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C
ethanal
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D
ethanoic acid
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Solution

The correct option is D ethanoic acid
C2H5OH+K2Cr2O7/H+CH3CHOCH3COOH
Ethanol is first oxidised to ethanal and then to ethanoic acid.
Potassium dichromate is a very strong oxidising agent, ethanol on oxidation, the dichromate ion (IV) solution which is orange in colour is reduced to a green colour Cr(III) ion solution. This reaction is used in detecting the presence of alcohol in breath in suspected drunken drivers.

Hence, the correct option is D.

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