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Question

Ethyl chloride on reduction with LiAlH4 gives compound x as an important product. Compound x on chlorination with one mole of Cl2 in the presence of light at ordinary temperature gives y. What is y?

A
CH3Cl
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B
CH2Cl2
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C
C2H5Cl
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D
C2H4Cl2
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Solution

The correct option is B C2H5Cl
In this reaction, ethyl chloride on reduction with lithium aluminium hydrate forms ethane which on chlorination gives ones again ethyl chloride.

Hence, option C is correct.

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