Ethyl iodide and n-propyl iodide are allowed to undergo Wurtz reaction. The alkane which will not be obtained in this reaction is:

butane

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propane

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pentane

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hexane

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Solution

The correct option is A propane
$C H_{3} C H_{2} I + C H_{3} C H_{2} C H_{2} I$
(Wurtz reaction) $↓ N a$
$C H_{3} C H_{2} C H_{2} C H_{3} b u t a n e + C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{3} h e x a n e + C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} p e n t a n e$
Ethyl iodide and n-propyl iodide are allowed to undergo Wurtz reaction and they form butane and hexane as self-addition products and pentane as cross addition product.
$∴$ So, propane will not be formed.

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