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Question
Ethylcyanide on reaction with sodium and C2H5OH forms :
Ethylcyanide on reaction with sodium and C2H5OH forms :
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Solution
The correct option is A propylamine
Ethylcyanide on reaction with sodium and ethonol forms propylamine.
CH3−CH2−C≡N+4[H]Na/ ethanol−−−−−−−→CH3−CH2−CH2−NH2
In this reaction, the nitrile group is hydrogenated to form a primary amine. This is a useful method to increase the length of a carbon chain in preparing a primary amine which contains one more carbon atom than the alkyl halide from which alkyl cyanide is obtained.
Ethylcyanide on reaction with sodium and ethonol forms propylamine.
CH3−CH2−C≡N+4[H]Na/ ethanol−−−−−−−→CH3−CH2−CH2−NH2
In this reaction, the nitrile group is hydrogenated to form a primary amine. This is a useful method to increase the length of a carbon chain in preparing a primary amine which contains one more carbon atom than the alkyl halide from which alkyl cyanide is obtained.
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