Ethylene diaminetetraacetate $(E D T A)$ ion is :

Tridentate ligand with three

" N "

donor atoms.

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Hexadentate ligand with four

" O "

and two

" N "

donor atoms.

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Unidentate ligand

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Bidentate ligand with two

" N "

donor atoms.

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Solution

The correct option is B Hexadentate ligand with four $" O "$ and two $" N "$ donor atoms.
Ethylene diaminetetraacetate $(E D T A)$ ion is a hexadented ligand having four donor oxygen atoms and two donor nitrogen atoms.

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E D T A^{4 -}

N - C o - O

[C o (E D T A)]^{-}

[F e (E D T A)]^{-}

$E D T A^{4 -}$ is ethylenediaminetetraacetate ion. The total number of $N - C o - O$ bonds in $[C o (E D T A)]^{-}$ complex ion is ___

C a^{2 +}

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