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Standard XII

Chemistry

Classification

Ethylidene di...

Question

Ethylidene dibromide is:

C H_{3} C H_{2} B r

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B r - C H_{2} - C H_{2} - B r

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C H_{3} - C H B r_{2}

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C H_{2} = C H B r

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Solution

The correct option is C $C H_{3} - C H B r_{2}$
Compound C is ethylidene dibromide or 1,1-dibromoethane.

Hence, the correct option is $C$ .

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Similar questions

An alkybromide(A) On treatment with Na and ether gives a hydrocarbon (B). (B) on treatment with HBr and Peroxide gives Br - $(C H_{2})_{6} - B r$ compound (A) is

Q. The decreasing order of rate of

S_{N} 2

is :

(I)

B r - C H_{2} - C H_{2} - B r

(II)

N = C - C H_{2} - B r

(III)

C H_{3} - C | B r H - C H_{3}

(IV)

C H_{3} - C H_{2} - B r

C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r + C H_{3} O^{-} C H_{3} O H - ---- \to 60^{o} C P r o d u c t (I)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r + (C H_{3})_{3} C O^{-} (C H_{3})_{3} C - O H - -------- \to 60^{o} C P r o d u c t (I I)

Select the correct options among the following.

Q. Select the member of each pair that shows faster rate of

S_{N} 2

reaction with

K I

in acetone.

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

(b)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

(c)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

(d)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

Q. Classify the following reactions in one of the reaction types studied.
a.

C H_{3} C H_{2} B r + H S^{⊖} \to C H_{3} C H_{2} S H + B r^{⊖}

{(C H_{3})}_{2} C = C H_{2} + H C l \to {(C H_{3})}_{2} (C l) C - C H_{3}

{(C H_{3})}_{3} C - C H_{2} O H + H B r \to {(C H_{3})}_{2} C (B r) C H_{2} C H_{3}

C H_{3} C H_{2} B r + H O^{⊖} \to C H_{2} = C H_{2}

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Ethylidene dibromide is:

The correct option is C CH3−CHBr2Compound C is ethylidene dibromide or 1,1-dibromoethane.Hence, the correct option is C.

The correct option is C $C H_{3} - C H B r_{2}$
Compound C is ethylidene dibromide or 1,1-dibromoethane.

Hence, the correct option is $C$ .