Question

Evaluate:
$1-(\frac{2}{3}+\frac{1}{6})$ = _____

• A. $\frac{1}{6}$
• B. $\frac{5}{6}$
• C. $\frac{1}{3}$
• D. $\frac{1}{2}$

Answer 1

The correct option is A $\frac{1}{6}$

We first find $\frac{2}{3}+\frac{1}{6}$.
Note that $\frac{2}{3}+\frac{1}{6}=\frac{(2\times 6)+(1\times 3)}{3\times 6}=\frac{12+3}{18}=\frac{15}{18}$
$=\frac{5}{6}$
Now, $1-(\frac{2}{3}+\frac{1}{6})=1-\frac{5}{6}$
$=\frac{1\times 6-5}{6}=\frac{6-5}{6}=\frac{1}{6}$