Evaluate- 30-26-15-8-6-3- -8-15-4-9-3-4-1-2-1

The correct option is D 25.1 30 [26 {15+(8 6 3)}] × 815÷49×34 12+1 = 30 [26 {15+(8 3)}] ×815÷49×34 12+1...........[removing vinculum] = 30 [26 {15+5}] ×815÷49× ...

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Byju's Answer

Standard VII

Mathematics

Division of Fractions

Evaluate: 30-...

Question

Evaluate: $30 - [26 - {15 + (8 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 6 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$

52.1

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25.1

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52.25

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22.23

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Solution

The correct option is B
25.1

$30 - [26 - {15 + (8 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 6 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$

$= 30 - [26 - {15 + (8 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$ ...........[removing vinculum]

$= 30 - [26 - {15 + 5}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$ ..................[removing small bracket]

$= 30 - [26 - 20] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$ ..................[removing curly bracket]

$= 30 - 6 \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$ ..................[removing square bracket]

$= 30 - 6 \times \frac{6}{5} \times \frac{3}{4} - \frac{1}{2} + 1$ .................. [division]

$= 30 - \frac{54}{10} - \frac{1}{2} + 1$ .................[multiplication]

$= 31 - \frac{54}{10} - \frac{1}{2}$ ...........[addition]

$= \frac{310 - 54 - 5}{10}$ ...................[subtraction]

$= 25.1$

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Similar questions

Q. Evaluate:

30 - [26 - {15 + (8 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 6 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1

Q. Evaluate.
(i) 9 × (− 3) × (− 6)
(ii) (− 5) × (− 10) × (− 7) × 2
(iii) (− 18) × (− 43) × 0
(iv) (− 9) × (− 8) × (− 1) × 1
(v) − 12 × (− 15) × 6 × 4
(vi) − 7 × (− 4) × (− 6) × (− 2)

Evaluate : $(i) \frac{5}{9} + \frac{- 7}{6} (i i) 4 + \frac{3}{- 5} (i i i) \frac{1}{- 15} + \frac{5}{- 12} (i v) \frac{5}{9} + \frac{3}{- 4} (v) \frac{- 8}{9} + \frac{- 5}{12} (v i) 0 + \frac{- 2}{7} (v i i) \frac{5}{- 11} + 0 (v i i i) 2 + \frac{- 3}{5} (i x) \frac{4}{- 9} + 1$

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Q. Median of the data:

1, 9, 4, 3, 7, 6, 8, 8, 12, 15

is.

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Evaluate: 30−[26−{15+(8−¯¯¯¯¯¯¯¯¯¯¯¯6−3)}]×815÷49×34−12+1

Evaluate: $30 - [26 - {15 + (8 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 6 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$