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Question

# Evaluate : (i) 59+−76(ii) 4+3−5(iii) 1−15+5−12(iv) 59+3−4(v) −89+−512(vi) 0+−27(vii) 5−11+0(viii) 2+−35(ix) 4−9+1

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Solution

## (i) 59+−76 ∴LCM of 9 and 6=2×3×3=18=5×29×2−7×36×3 (∵LCM of 9 and 6=18)=10−2118=−118(ii) 4+3−5=41+(3−5)=41−35=4×51×5−3×15×1 (∵LCM of 1 and5=5)=20−35−175=325(iii) 1−15+5−12=−115+(5−12)=−115−512 ∴LCM of 15 and 12=2×2×3×5=60=−1×415×4−5×512×5 (∵LCM of 15 and 12=60)=−4−2560=−2960(iv) 59+3−4 =59−34(∴LCM of 9 and 4=2×2×3×3=36)=5×49×4−3×94×9=20−2736=−736 (∵LCM of 9 and 4=36)=−736(v) −89+−512 (∴LCM of 9,12=2×2×3×3=36)=−8×49×4−5×312×3=−32−1536 (∵LCM of 9 and 12=36)=−4736(vi) 0+−27=0×71×7−2×17×1 (∵LCM of 0 and 7=7)=0−27=−27(vii) 5−11+0=−5×111×1+0×111×11 (∵LCM of 0 and 11=11)=−5+011=−511(viii) 2+−35=21−35 (∵LCM of 1 and 5=5)=2×51×5−3×15×1=10−35=75=125(ix) 4−9+1=−49−11 (∵LCM of 9 and 1=9)=−4×11×9+1×91×9=−4+99=59

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