Evaluate - 39 y 3 50y 2 -98 - 16 y 2 5y-7

39y^3(50y^2 98)× reciprocal of 16y^2(5y+7) =39y^3(50y^2 98)16y^2(5y+7) =39y^3× 2(25y^2 49)16y^2(5y+7) =78y(5y 7)(5y+7)16(5y+7) =3 ...

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Reciprocal of a Number

Evaluate : 3...

Question

Evaluate :
$39 y^{3} ({50 y}^{2} - 98) \div 16 y^{2} (5 y + 7)$

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Factorise and divide the expressions given

i.) $(m^{2} - 11 m - 42) \div (m + 3)$

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