Evaluate $(49)^{2}$ using the identity $(a - b)^{2} = a^{2} - 2 a b + b^{2}$ .

Open in App

Solution

Using $(a - b)^{2}$ = $a^{2} - 2 a b + b^{2}$ to calculate the value of $(49)^{2}$
We can write $(49)^{2}$ as $(50 - 1)^{2}$
$(50 - 1)^{2}$ $= 50^{2} - 2 \times 50 \times 1 + 1^{2}$ $=$ $2500 - 100 + 1$
The answer is $2401$

Suggest Corrections

Similar questions

Evaluate using the identity:

(i) (49)²; (ii) (9.8)²; (iii) (59)²; (iv) (198)².

(53)^{2}

(a + b)^{2} = a^{2} + 2 a b + b^{2}

209^{2}

{(a + b)}^{2} = a^{2} + 2 a b + b^{2}

\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}

(a + b)^{2} = a^{2} + 2 a b + b^{2}

(a + 6)^{2}

Join BYJU'S Learning Program